WebAnswer (1 of 8): \tan\,A = \dfrac{1}{2}\qquad \cot\,B = 3\implies \tan\,B = \dfrac{1}{3} \tan (A + B) = \dfrac{\tan\,A + \tan\,B}{1 - \tan\,A\tan\,B} \implies\tan (A ... Web29 mrt. 2024 · Ex 8.3, 4 If tan A = cot B, prove that A + B = 90 . Given tan A = cot B To solve this we should know relation between tan and cot Now, We know that cot θ = tan (90 - θ) Putting value of cot B tan A = tan (90 - B) Comparing angles A = 90 - B A + B = 90 …
Επίλυση cotA+tanB/cotB+tanA Microsoft Math Solver
Web欢迎来到e座教育网! 机构大全. 课程大全. 商务合作. 官微. 手机 Webtan A = 3 4 A+B=90° ⇒B=90°-A ⇒ cot B = cot ( 90 ° - A) ⇒ cot B = tan A ⇒ cot B = 3 4 [ cot ( 90 ° - A) = tan A] Hence the value of cot B is 3 4 Concept: Trigonometric Ratios of Complementary Angles Is there an error in this question or solution? Chapter 10: Trigonometric Ratios - Exercise 10.4 [Page 55] Q 10 Q 9 Q 11 RD Sharma Class 10 Maths scum workbench map
Tan a – tanb = x, cotb -cota = Y, THEN cot (a-b)= - askIITians
WebIf tan A = cot B, prove that A + B = 90° Solution: We will be using the trigonometric ratios of complementary angles to solve the given question. tan (90° - θ) = cot θ Given that: tan A … Web2tanB+cotB=tanA. 2tan^2B+1=tanAtanB. tan^2B=tanAtanB-1. Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the … Web【答案】分析:先利用同角三角函数的基本关系和二倍角公式化简整理题设等式求得cos = 进而求得A+B=90°进而求得①tanA•cotB=tanA•tanA等式不一定成立,排除;②利用两角和公式化简,利用正弦函数的性质求得其范围符合,②正确; ③sin 2 A+cos 2 B=2sin 2 A不一定等于1,排除③;④利用同角三角函数的 ... scum worth buying